Call for Solutions to
A Large Polynomial System
from Differential Equations
... in order to settle the classical Kukles problem
that is still open ...
The polynomial system is:
P9 = {v5, ..., v19} = 0, where
No. of terms
Total degree
MaxLIC*
|
v5
13 4 2
|
v7
49 6 4
|
v9
131 8 6
|
v11
292 10 9
|
v13
577 12 13
|
v15
1046 14 17
|
v17
1775 16 22
|
v19
2859 18 27
|
P7 = {v5, ..., v15} = 0 if and only if one of the following holds:
- Q1 = 0;
- Q2 = 0, f1
0;
- Q3 = 0, f1 ·
f2
0;
- Q4 = 0, f1 · f2 ·
f3
0;
- Q5 = 0, a03 · f1 · f2 ·
f3
0;
- Q6 = 0, a03 · f1 · f2 · f3 ·
f4
0.
Q6 consists of six polynomials, of which the following four in
a20, a11, a02, a03 are very large:
No. of terms
Total degree
MaxLIC
|
w9
458 26 16
|
w11
539 28 18
|
w13
1102 36 24
|
w15
1946 44 32
|
*MaxLIC = "Maximum Length of Integer Coefficients"
- Decompose the polynomial set Q1 and systems
[Q2, {f1}], [Q3, {f1, f2}], [Q6, {a03, f1, ..., f4}]
into triangular systems.
- Decompose the algebraic variety defined by P7 = 0
into irreducible components, using or without using the Qi.
Please send your comments, suggestions, and solutions to
Dongming.Wang@imag.fr.
Known Results
- All the known solutions of P9 = 0 are
C1 = 0,
K2 = 0 and K4 = {a20, a02, a03} = 0.
- {v5, ..., v19, ...} = 0 has no other real solutions of positive dimension.
- C1 can be decomposed into three irreducible components K1,
K3 = {a11, a03} and C0.
- K2 and K1 can be obtained from [Q4, {f1, f2, f3}]
and [Q5, {a03, f1, f2, f3}] respectively.
- C0 is contained in Q6.
Conjecture. C1 = 0, K2 = 0, and K4 = 0
cover all the real solutions of {v5, ..., v19, ...} = 0.
Background
- Kukles (1944) showed that v5 = v7 = ... = v19 = ... = 0 "if and
only if" one of the following holds: K1 = 0, K2 = 0, K3 = 0, K4 = 0.
- The incompleteness of Kukles' solutions were discovered by
Cherkas (1978), Jin and Wang (1990), and Christopher and Lloyd
(1990).
- The above results were obtained by Christopher, Lloyd and Pearson
(1990-94) and Wang (1996-97).
For further information see JSC 28 (1999): 303-315 or contact
Dongming
Wang.